566. Reshape the Matrix
Read the full problem statement on LeetCode.
Difficulty: easy Acceptance: 64% Topics: Array, Matrix, Simulation
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Reference solution (spoiler · python)
# Time: O(m * n)
# Space: O(m * n)
class Solution(object):
def matrixReshape(self, nums, r, c):
"""
:type nums: List[List[int]]
:type r: int
:type c: int
:rtype: List[List[int]]
"""
if not nums or \
r*c != len(nums) * len(nums[0]):
return nums
result = [[0 for _ in xrange(c)] for _ in xrange(r)]
count = 0
for i in xrange(len(nums)):
for j in xrange(len(nums[0])):
result[count/c][count%c] = nums[i][j]
count += 1
return result
Solution from kamyu104/LeetCode-Solutions · MIT
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