25. Reverse Nodes in k-Group

# Time:  O(n)
# Space: O(1)

class ListNode(object):
    def __init__(self, x):
        self.val = x
        self.next = None

    def __repr__(self):
        if self:
            return "{} -> {}".format(self.val, repr(self.next))

class Solution(object):
    # @param head, a ListNode
    # @param k, an integer
    # @return a ListNode
    def reverseKGroup(self, head, k):
        dummy = ListNode(-1)
        dummy.next = head

        cur, cur_dummy = head, dummy
        length = 0

        while cur:
            next_cur = cur.next
            length = (length + 1) % k

            if length == 0:
                next_dummy = cur_dummy.next
                self.reverse(cur_dummy, cur.next)
                cur_dummy = next_dummy

            cur = next_cur

        return dummy.next

    def reverse(self, begin, end):
            first = begin.next
            cur = first.next

            while cur != end:
                first.next = cur.next
                cur.next = begin.next
                begin.next = cur
                cur = first.next

Solution from kamyu104/LeetCode-Solutions · MIT