LC-2415 Medium LeetCode

2415. Reverse Odd Levels of Binary Tree

Tree Depth-First Search Breadth-First Search Binary Tree

Read the full problem statement on LeetCode.

Difficulty: medium Acceptance: 87% Topics: Tree, Depth-First Search, Breadth-First Search, Binary Tree

Reading material

Reference solution (spoiler · python)

# Time:  O(n)
# Space: O(n)

# Definition for a binary tree node.
class TreeNode(object):
    def __init__(self, val=0, left=None, right=None):
        pass


# bfs
class Solution(object):
    def reverseOddLevels(self, root):
        """
        :type root: Optional[TreeNode]
        :rtype: Optional[TreeNode]
        """
        q = [root]
        parity = 0
        while q:
            if parity:
                left, right = 0, len(q)-1
                while left < right:
                    q[left].val, q[right].val = q[right].val, q[left].val
                    left += 1
                    right -= 1
            if not q[0].left:
                break
            new_q = []
            for node in q:
                new_q.append(node.left)
                new_q.append(node.right)
            q = new_q       
            parity ^= 1
        return root

Solution from kamyu104/LeetCode-Solutions · MIT