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LC-0493 Hard LeetCode

493. Reverse Pairs

Read the full problem statement on LeetCode.
Difficulty: hard Acceptance: 32% Topics: Array, Binary Search, Divide and Conquer, Binary Indexed Tree, Segment Tree, Merge Sort, Ordered Set
View full problem on LeetCode
Reference solution (spoiler · python)
# Time:  O(nlogn)
# Space: O(n)

class Solution(object):
    def reversePairs(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        def merge(nums, start, mid, end):
            r = mid + 1
            tmp = []
            for i in xrange(start, mid + 1):
                while r <= end and nums[i] > nums[r]:
                    tmp.append(nums[r])
                    r += 1
                tmp.append(nums[i])
            nums[start:start+len(tmp)] = tmp

        def countAndMergeSort(nums, start, end):
            if end - start <= 0:
                return 0

            mid = start + (end - start) / 2
            count = countAndMergeSort(nums, start, mid) + countAndMergeSort(nums, mid + 1, end)
            r = mid + 1
            for i in xrange(start, mid + 1):
                while r <= end and nums[i] > nums[r] * 2:
                    r += 1
                count += r - (mid + 1)
            merge(nums, start, mid, end)
            return count

        return countAndMergeSort(nums, 0, len(nums) - 1)

Solution from kamyu104/LeetCode-Solutions · MIT