Skip to content
LC-0048 Medium LeetCode

48. Rotate Image

Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 78% Topics: Array, Math, Matrix
View full problem on LeetCode
Reference solution (spoiler · python)
# Time:  O(n^2)
# Space: O(1)

class Solution(object):
    # @param matrix, a list of lists of integers
    # @return a list of lists of integers
    def rotate(self, matrix):
        n = len(matrix)

        # anti-diagonal mirror
        for i in xrange(n):
            for j in xrange(n - i):
                matrix[i][j], matrix[n-1-j][n-1-i] = matrix[n-1-j][n-1-i], matrix[i][j]

        # horizontal mirror
        for i in xrange(n / 2):
            for j in xrange(n):
                matrix[i][j], matrix[n-1-i][j] = matrix[n-1-i][j], matrix[i][j]

        return matrix

# Time:  O(n^2)
# Space: O(n^2)
class Solution2(object):
    # @param matrix, a list of lists of integers
    # @return a list of lists of integers
    def rotate(self, matrix):
        return [list(reversed(x)) for x in zip(*matrix)]

Solution from kamyu104/LeetCode-Solutions · MIT