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LC-0990 Medium LeetCode

990. Satisfiability of Equality Equations

Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 51% Topics: Array, String, Union Find, Graph
View full problem on LeetCode
Reference solution (spoiler · python)
# Time:  O(n)
# Space: O(1)

class UnionFind(object):
    def __init__(self, n):
        self.set = range(n)

    def find_set(self, x):
        if self.set[x] != x:
            self.set[x] = self.find_set(self.set[x])  # path compression.
        return self.set[x]

    def union_set(self, x, y):
        x_root, y_root = map(self.find_set, (x, y))
        if x_root == y_root:
            return False
        self.set[min(x_root, y_root)] = max(x_root, y_root)
        return True


class Solution(object):
    def equationsPossible(self, equations):
        """
        :type equations: List[str]
        :rtype: bool
        """
        union_find = UnionFind(26)
        for eqn in equations:
            x = ord(eqn[0]) - ord('a')
            y = ord(eqn[3]) - ord('a')
            if eqn[1] == '=':
                union_find.union_set(x, y)
        for eqn in equations:
            x = ord(eqn[0]) - ord('a')
            y = ord(eqn[3]) - ord('a')
            if eqn[1] == '!':
                if union_find.find_set(x) == union_find.find_set(y):
                    return False
        return True


# Time:  O(n)
# Space: O(1)
class Solution2(object):
    def equationsPossible(self, equations):
        """
        :type equations: List[str]
        :rtype: bool
        """
        graph = [[] for _ in xrange(26)]

        for eqn in equations:
            x = ord(eqn[0]) - ord('a')
            y = ord(eqn[3]) - ord('a')
            if eqn[1] == '!':
                if x == y:
                    return False
            else:
                graph[x].append(y)
                graph[y].append(x)

        color = [None]*26
        c = 0
        for i in xrange(26):
            if color[i] is not None:
                continue
            c += 1
            stack = [i]
            while stack:
                node = stack.pop()
                for nei in graph[node]:
                    if color[nei] is not None:
                        continue
                    color[nei] = c
                    stack.append(nei)

        for eqn in equations:
            if eqn[1] != '!':
                continue
            x = ord(eqn[0]) - ord('a')
            y = ord(eqn[3]) - ord('a')
            if color[x] is not None and \
               color[x] == color[y]:
                return False
        return True

Solution from kamyu104/LeetCode-Solutions · MIT