671. Second Minimum Node In a Binary Tree
Read the full problem statement on LeetCode.
Difficulty: easy Acceptance: 45% Topics: Tree, Depth-First Search, Binary Tree
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n)
# Space: O(h)
import heapq
class Solution(object):
def findSecondMinimumValue(self, root):
"""
:type root: TreeNode
:rtype: int
"""
def findSecondMinimumValueHelper(root, max_heap, lookup):
if not root:
return
if root.val not in lookup:
heapq.heappush(max_heap, -root.val)
lookup.add(root.val)
if len(max_heap) > 2:
lookup.remove(-heapq.heappop(max_heap))
findSecondMinimumValueHelper(root.left, max_heap, lookup)
findSecondMinimumValueHelper(root.right, max_heap, lookup)
max_heap, lookup = [], set()
findSecondMinimumValueHelper(root, max_heap, lookup)
if len(max_heap) < 2:
return -1
return -max_heap[0]
Solution from kamyu104/LeetCode-Solutions · MIT
Similar questions