1091. Shortest Path in Binary Matrix
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 50% Topics: Array, Breadth-First Search, Matrix
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n^2)
# Space: O(n)
import collections
class Solution(object):
def shortestPathBinaryMatrix(self, grid):
"""
:type grid: List[List[int]]
:rtype: int
"""
directions = [(-1, -1), (-1, 0), (-1, 1), \
( 0, -1), ( 0, 1), \
( 1, -1), ( 1, 0), ( 1, 1)]
result = 0
q = collections.deque([(0, 0)])
while q:
result += 1
next_depth = collections.deque()
while q:
i, j = q.popleft()
if 0 <= i < len(grid) and \
0 <= j < len(grid[0]) and \
not grid[i][j]:
grid[i][j] = 1
if i == len(grid)-1 and j == len(grid)-1:
return result
for d in directions:
next_depth.append((i+d[0], j+d[1]))
q = next_depth
return -1
Solution from kamyu104/LeetCode-Solutions · MIT
Similar questions