909. Snakes and Ladders
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 44% Topics: Array, Breadth-First Search, Matrix
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n^2)
# Space: O(n^2)
import collections
class Solution(object):
def snakesAndLadders(self, board):
"""
:type board: List[List[int]]
:rtype: int
"""
def coordinate(n, s):
a, b = divmod(s-1, n)
r = n-1-a
c = b if r%2 != n%2 else n-1-b
return r, c
n = len(board)
lookup = {1: 0}
q = collections.deque([1])
while q:
s = q.popleft()
if s == n*n:
return lookup[s]
for s2 in xrange(s+1, min(s+6, n*n)+1):
r, c = coordinate(n, s2)
if board[r][c] != -1:
s2 = board[r][c]
if s2 not in lookup:
lookup[s2] = lookup[s]+1
q.append(s2)
return -1
Solution from kamyu104/LeetCode-Solutions · MIT
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