2741. Special Permutations
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 28% Topics: Array, Dynamic Programming, Bit Manipulation, Bitmask
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n^2 * 2^n)
# Space: O(n * 2^n)
# backtracking, memoization
class Solution(object):
def specialPerm(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
MOD = 10**9+7
def backtracking(i, mask):
if mask == (1<<len(nums))-1:
return 1
if lookup[i+1][mask] == -1:
total = 0
for j in xrange(len(nums)):
if mask&(1<<j):
continue
if not (i == -1 or nums[i]%nums[j] == 0 or nums[j]%nums[i] == 0):
continue
total = (total+backtracking(j, mask|(1<<j)))%MOD
lookup[i+1][mask] = total
return lookup[i+1][mask]
lookup = [[-1]*(1<<len(nums)) for _ in xrange(len(nums)+1)]
return backtracking(-1, 0)
Solution from kamyu104/LeetCode-Solutions · MIT