3427. Sum of Variable Length Subarrays
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Difficulty: easy Acceptance: 85% Topics: Array, Prefix Sum
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Reference solution (spoiler · python)
# Time: O(n)
# Space: O(n)
# difference array
class Solution(object):
def subarraySum(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
diff = [0]*(len(nums)+1)
for i, x in enumerate(nums):
diff[max(i-x, 0)] += 1
diff[i+1] -= 1
for i in xrange(len(nums)):
diff[i+1] += diff[i]
return sum(nums[i]*diff[i] for i in xrange(len(nums)))
Solution from kamyu104/LeetCode-Solutions · MIT