1930. Unique Length-3 Palindromic Subsequences
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Difficulty: medium Acceptance: 71% Topics: Hash Table, String, Bit Manipulation, Prefix Sum
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Reference solution (spoiler · python)
# Time: O(n)
# Space: O(1)
class Solution(object):
def countPalindromicSubsequence(self, s):
"""
:type s: str
:rtype: int
"""
first, last = [len(s)]*26, [-1]*26
for i, c in enumerate(s):
first[ord(c)-ord('a')] = min(first[ord(c)-ord('a')], i)
last[ord(c)-ord('a')] = max(last[ord(c)-ord('a')], i)
return sum(len(set(s[i] for i in xrange(first[c]+1, last[c]))) for c in xrange(26))
Solution from kamyu104/LeetCode-Solutions · MIT
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