139. Word Break
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 48% Topics: Array, Hash Table, String, Dynamic Programming, Trie, Memoization
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Reference solution (spoiler · python)
# Time: O(n * l^2)
# Space: O(n)
class Solution(object):
def wordBreak(self, s, wordDict):
"""
:type s: str
:type wordDict: Set[str]
:rtype: bool
"""
n = len(s)
max_len = 0
for string in wordDict:
max_len = max(max_len, len(string))
can_break = [False for _ in xrange(n + 1)]
can_break[0] = True
for i in xrange(1, n + 1):
for l in xrange(1, min(i, max_len) + 1):
if can_break[i-l] and s[i-l:i] in wordDict:
can_break[i] = True
break
return can_break[-1]
Solution from kamyu104/LeetCode-Solutions · MIT
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