LC-0094 Easy LeetCode

94. Binary Tree Inorder Traversal

Stack Tree Depth-First Search Binary Tree

Read the full problem statement on LeetCode.

Difficulty: easy Acceptance: 78% Topics: Stack, Tree, Depth-First Search, Binary Tree

Reading material

Stacks & Queues 11 min Trees & Traversals 18 min

Reference solution (spoiler · python)

# Time:  O(n)
# Space: O(1)

class TreeNode(object):
    def __init__(self, x):
        self.val = x
        self.left = None
        self.right = None


# Morris Traversal Solution
class Solution(object):
    def inorderTraversal(self, root):
        """
        :type root: TreeNode
        :rtype: List[int]
        """
        result, curr = [], root
        while curr:
            if curr.left is None:
                result.append(curr.val)
                curr = curr.right
            else:
                node = curr.left
                while node.right and node.right != curr:
                    node = node.right

                if node.right is None:
                    node.right = curr
                    curr = curr.left
                else:
                    result.append(curr.val)
                    node.right = None
                    curr = curr.right

        return result


# Time:  O(n)
# Space: O(h)
# Stack Solution
class Solution2(object):
    def inorderTraversal(self, root):
        """
        :type root: TreeNode
        :rtype: List[int]
        """
        result, stack = [], [(root, False)]
        while stack:
            root, is_visited = stack.pop()
            if root is None:
                continue
            if is_visited:
                result.append(root.val)
            else:
                stack.append((root.right, False))
                stack.append((root, True))
                stack.append((root.left, False))
        return result

Solution from kamyu104/LeetCode-Solutions · MIT