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LC-0098 Medium LeetCode

98. Validate Binary Search Tree

Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 34% Topics: Tree, Depth-First Search, Binary Search Tree, Binary Tree
View full problem on LeetCode
Reference solution (spoiler · python)
# Time:  O(n)
# Space: O(1)

class TreeNode(object):
    def __init__(self, x):
        self.val = x
        self.left = None
        self.right = None

# Morris Traversal Solution
class Solution(object):
    # @param root, a tree node
    # @return a list of integers
    def isValidBST(self, root):
        prev, cur = None, root
        while cur:
            if cur.left is None:
                if prev and prev.val >= cur.val:
                    return False
                prev = cur
                cur = cur.right
            else:
                node = cur.left
                while node.right and node.right != cur:
                    node = node.right

                if node.right is None:
                    node.right = cur
                    cur = cur.left
                else:
                    if prev and prev.val >= cur.val:
                        return False
                    node.right = None
                    prev = cur
                    cur = cur.right

        return True


# Time:  O(n)
# Space: O(h)
class Solution2(object):
    # @param root, a tree node
    # @return a boolean
    def isValidBST(self, root):
        return self.isValidBSTRecu(root, float("-inf"), float("inf"))

    def isValidBSTRecu(self, root, low, high):
        if root is None:
            return True

        return low < root.val and root.val < high \
            and self.isValidBSTRecu(root.left, low, root.val) \
            and self.isValidBSTRecu(root.right, root.val, high)


Solution from kamyu104/LeetCode-Solutions · MIT