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LC-0070 Easy LeetCode

70. Climbing Stairs

Read the full problem statement on LeetCode.
Difficulty: easy Acceptance: 53% Topics: Math, Dynamic Programming, Memoization
View full problem on LeetCode
Reference solution (spoiler · python)
# Time:  O(logn)
# Space: O(1)

import itertools


class Solution(object):
    def climbStairs(self, n):
        """
        :type n: int
        :rtype: int
        """
        def matrix_expo(A, K):
            result = [[int(i==j) for j in xrange(len(A))] \
                      for i in xrange(len(A))]
            while K:
                if K % 2:
                    result = matrix_mult(result, A)
                A = matrix_mult(A, A)
                K /= 2
            return result

        def matrix_mult(A, B):
            ZB = zip(*B)
            return [[sum(a*b for a, b in itertools.izip(row, col)) \
                     for col in ZB] for row in A]

        T = [[1, 1],
             [1, 0]]
        return matrix_mult([[1,  0]], matrix_expo(T, n))[0][0]  # [a0, a(-1)] * T^n


# Time:  O(n)
# Space: O(1)
class Solution2(object):
    """
    :type n: int
    :rtype: int
    """
    def climbStairs(self, n):
        prev, current = 0, 1
        for i in xrange(n):
            prev, current = current, prev + current,
        return current

Solution from kamyu104/LeetCode-Solutions · MIT