2320. Count Number of Ways to Place Houses
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 43% Topics: Dynamic Programming
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(logn)
# Space: O(1)
import itertools
# matrix exponentiation
class Solution(object):
def countHousePlacements(self, n):
"""
:type n: int
:rtype: int
"""
MOD = 10**9+7
def matrix_mult(A, B):
ZB = zip(*B)
return [[sum(a*b % MOD for a, b in itertools.izip(row, col)) % MOD for col in ZB] for row in A]
def matrix_expo(A, K):
result = [[int(i == j) for j in xrange(len(A))] for i in xrange(len(A))]
while K:
if K % 2:
result = matrix_mult(result, A)
A = matrix_mult(A, A)
K /= 2
return result
T = [[1, 1],
[1, 0]]
return pow(matrix_mult([[2, 1]], matrix_expo(T, n-1))[0][0], 2, MOD) # [a1, a0] * T^(n-1) = [an, a(n-1)]
# Time: O(n)
# Space: O(1)
# dp
class Solution2(object):
def countHousePlacements(self, n):
"""
:type n: int
:rtype: int
"""
MOD = 10**9+7
prev, curr = 1, 2
for _ in xrange(n-1):
prev, curr = curr, (prev+curr)%MOD
return pow(curr, 2, MOD)
Solution from kamyu104/LeetCode-Solutions · MIT
Similar questions