996. Number of Squareful Arrays
Read the full problem statement on LeetCode.
Difficulty: hard Acceptance: 50% Topics: Array, Hash Table, Math, Dynamic Programming, Backtracking, Bit Manipulation, Bitmask
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Reference solution (spoiler · python)
# Time: O(n!)
# Space: O(n^2)
import collections
class Solution(object):
def numSquarefulPerms(self, A):
"""
:type A: List[int]
:rtype: int
"""
def dfs(candidate, x, left, count, result):
count[x] -= 1
if left == 0:
result[0] += 1
for y in candidate[x]:
if count[y]:
dfs(candidate, y, left-1, count, result)
count[x] += 1
count = collections.Counter(A)
candidate = {i: {j for j in count if int((i+j)**0.5) ** 2 == i+j}
for i in count}
result = [0]
for x in count:
dfs(candidate, x, len(A)-1, count, result)
return result[0]
Solution from kamyu104/LeetCode-Solutions · MIT
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