47. Permutations II
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 61% Topics: Array, Backtracking, Sorting
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n * n!)
# Space: O(n)
class Solution(object):
def permuteUnique(self, nums):
"""
:type nums: List[int]
:rtype: List[List[int]]
"""
nums.sort()
result = []
used = [False] * len(nums)
self.permuteUniqueRecu(result, used, [], nums)
return result
def permuteUniqueRecu(self, result, used, cur, nums):
if len(cur) == len(nums):
result.append(cur + [])
return
for i in xrange(len(nums)):
if used[i] or (i > 0 and nums[i-1] == nums[i] and not used[i-1]):
continue
used[i] = True
cur.append(nums[i])
self.permuteUniqueRecu(result, used, cur, nums)
cur.pop()
used[i] = False
class Solution2(object):
# @param num, a list of integer
# @return a list of lists of integers
def permuteUnique(self, nums):
solutions = [[]]
for num in nums:
next = []
for solution in solutions:
for i in xrange(len(solution) + 1):
candidate = solution[:i] + [num] + solution[i:]
if candidate not in next:
next.append(candidate)
solutions = next
return solutions
Solution from kamyu104/LeetCode-Solutions · MIT